Evaluating integral involving Heaviside function.

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SUMMARY

The integral ∫ (t - 1)^2 U(t - 2)dt on the interval [0, 5] can be evaluated by decomposing it into two parts: [0, 2] and [2, 5]. The Heaviside function U(t - 2) equals 0 for t < 2 and 1 for t > 2. Therefore, the integral simplifies to evaluating ∫(t - 1)^2 dt over the interval [2, 5], which is the correct approach to solving the problem.

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Homework Statement


Evaluate ∫ (t - 1)^2 U(t - 2)dt on the interval [0, 5]


Homework Equations


τ = 2, b = 5.
U(t - τ) = 0, t < τ and 1, t > τ.


The Attempt at a Solution


Decompose integral up into two parts [0, 2] and [2,5].
U(t - 2) will = 0 on the first interval as t < τ and it will = 1 on the second as t > τ. From there it's just a case of evaluating ∫(t - 1)^2 dt on [2,5].
Does this sound correct or have I gone wrong somewhere?
Thanks.
 
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That approach looks fine to me.
 
Good stuff. Thanks.
 

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