Evaluating Vector Spaces: V = {(0,1), (1,0)}

Kosh11
Messages
5
Reaction score
0

Homework Statement



Are the following vector spaces over \Re, with the usual notion of
addition and scalar multiplication: V = {(0, 1), (1, 0)}

Homework Equations



definition of vector space

The Attempt at a Solution



I'm a little confused by what this means. Am I correcting in thinking in drawing a line from the origin to (0,1) and another from the origin to (1,0) and all the vectors contained in those two lines belong to V? Then I'm unsure as to whether or nor this a vector space. Addition and scalar multiplication seem to hold, but I'm not sure and I'm lost on how to prove it either true or false.
 
Physics news on Phys.org
as its written, i would read that as the subset of R^2, with two elements, the vectors ( 0,1) and (1,0), which is clearly not a vector subspace

maybe you should write the question just as it is aksed for clarity
 
I would interpret that exactly as it is given- as set notation- that (0, 1) and (1, 0) are the only objects in the set. Nothing is said about a "span" or combinations of those vectors. In particular, the 0 vector, (0, 0), is not in the set.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top