Expectation Values of x & p for Wavefunction u(x,0)

In summary, <p> is defined as the integral of the wavefunction multiplied by the momentum operator and its complex conjugate. This definition differs from the formula for p found in the book, which is <p> = m*d/dt<x>. This is due to the fact that p and <p> are not the same thing.
  • #1
Geocentric
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0

Homework Statement


A particle is represented(at t=0) by the wavefunction

u(x,0) = A(a^2 - x^2) if -a<x<a
= 0 otherwise
Determine <x> & <p>.
It is given in the book that in this case <p> [tex]\neq[/tex] m*d/dt<x>. Could someone please tell me the reason for this?

Homework Equations





The Attempt at a Solution

 
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  • #2
because if you use <p> = m d<x>/dt, you would determine the expectation value of the momentum via that of x.
But <p> is given only by ∫u p u* dx - it's a definition.
 
Last edited:
  • #3
Rick88 said:
because if you use <p> = m d<x>/dt, you would determine the expectation value of the momentum via that of x.
But <p> is given only by ∫u p u* dx - it's a definition.

What I don't understand is that according to Ehrenfest theorem,
<p> = m* d/dt<x>
Why is this not true in this case?
 
  • #4
How does your book DEFINE p mathematically?
 
  • #5
The integral is just the definition of <p>.
p and <p> are not the same thing, so you can't use the formula for p to find <p>.
 

1. What is the significance of expectation values in quantum mechanics?

Expectation values represent the average value of a physical quantity, such as position or momentum, in a quantum state. They are essential in predicting the behavior of particles in quantum systems.

2. How are expectation values calculated for a wavefunction?

To calculate the expectation value of a physical quantity, such as position or momentum, for a wavefunction, the wavefunction must first be squared to find the probability distribution. Then, the integral of the product of the physical quantity and the squared wavefunction is taken over all possible values of the variable.

3. What is the difference between expectation values of position and momentum?

The expectation value of position represents the average position of a particle in space, while the expectation value of momentum represents the average momentum of a particle. They are related through the Heisenberg uncertainty principle, where the product of their uncertainties cannot be less than a certain value.

4. How do expectation values change over time?

In quantum mechanics, the expectation values of observables, such as position and momentum, can change over time due to the time evolution of the wavefunction. This change is governed by the Schrödinger equation.

5. How do expectation values relate to the uncertainty principle?

The uncertainty principle states that the product of the uncertainties in position and momentum must be greater than or equal to a certain value. This is directly related to the concept of expectation values, as the uncertainty in a physical quantity is inversely proportional to its expectation value. This means that the more precisely we know the expectation value of a quantity, the less certain we are about its exact value.

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