Experimentally finding focal length of small biconvex lens?

AI Thread Summary
To experimentally find the focal length of small biconvex lenses, one effective method involves focusing sunlight onto a piece of white paper by adjusting the distance between the lens and the paper until a clear image is formed. While using three parallel lasers is suggested, the beams may exceed the lens diameter, making two beams a potential alternative. For indoor experiments, a distant bright lamp can also serve as a light source, although the distance should be at least ten times the focal length for accurate measurements. The lenses, made from acrylic and polished, are expected to have a power of around -3 diopters. Consulting an optician with a lensmeter can provide precise measurements and assess the lens quality.
Rachelrific
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I have fabricated a few biconvex lens (12mm diameter) for an experiment and am trying to find their focal lengths. My though is to set up three parallel lasers and find where the beams converge. However, even with the smallest laser diodes I could find, three beams surpass the diameter of the lens. Would two beams be sufficient? Or does anyone have an alternative method of experimentally finding the focal length of small biconvex lens?
 
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Rachelrific said:
experimentally finding the focal length of small biconvex lens
1) Take the lens and a piece of white paper out in direct sunlight.
2) Focus the Sun on the paper by varying the lens-to-paper distance.
3) When in focus, the distance from the lens to the paper is the focal length.
 
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Well done fabricating your lens - that is no mean feat. (I do this for a living - contact lenses are concave/convex lenses about 14 mm in diameter).

What radius did you intend to make back and front? And what is it made of, glass or acrylic/perspex?
 
Tom.G said:
1) Take the lens and a piece of white paper out in direct sunlight.
2) Focus the Sun on the paper by varying the lens-to-paper distance.
3) When in focus, the distance from the lens to the paper is the focal length.
Would this work with a far away light source indoors, like a bright lamp across the room? There's a liquid component to my lens and I don't want it to freeze outside.
 
Bandit127 said:
Well done fabricating your lens - that is no mean feat. (I do this for a living - contact lenses are concave/convex lenses about 14 mm in diameter).

What radius did you intend to make back and front? And what is it made of, glass or acrylic/perspex?
Should be around -3 diopters. I made them out of acrylic (CNC'ed then heavily polished).
 
Rachelrific said:
Would this work with a far away light source indoors, like a bright lamp across the room? There's a liquid component to my lens and I don't want it to freeze outside.
Yeah, that should work. You can calculate the error introduced by the finite distance to the light source to see if it's acceptable to you.
 
Rachelrific said:
Should be around -3 diopters. I made them out of acrylic (CNC'ed then heavily polished).
If you are working in dioptres then your friendly optician/optometrist will be have exactly the right instrument to measure the power of your lens. They will also be able to assess the quality of the focus.
https://en.wikipedia.org/wiki/Lensmeter

(If your lens is bi-convex it will have a plus power BTW).

Well done polishing it too - it is a tricky process and there is definitely an art to it.
 
As long as your source distance is greater then 10x the focal length, a direct measurement will be as good as your ability to measure.
 
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