Explaining Difference in pH Values of Hydrocloric & Ethanoic Acids

AI Thread Summary
The discussion centers on the differing pH values of 0.100 mol/dm³ solutions of hydrochloric acid and ethanoic acid, which are both monoprotic acids. Hydrochloric acid has a lower pH of 1 due to its stronger acidity and greater tendency to release protons compared to ethanoic acid, which has a pH of approximately 3. The strength of an acid is influenced by its molecular structure and the stability of the resulting negative ion after proton loss. Additionally, factors such as electronegativity and solvent interactions can affect acidity, with acetic acid being less likely to lose its proton due to strong bonding with electronegative oxygen atoms. Overall, the discussion clarifies that the differences in pH arise from the inherent properties of the acids rather than their concentrations.
Jack16
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Hello People,
I am a new member and i really think this forum is very helpful...
I got a question...
The pH values of 0.100moldm-3 solutions of hydrocloric acid and ethanoic acid are 1 and aproximately 3 respectively. Explain the difference.

Thanks already...
 
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Hi Jack,

I suppose that your question is: why are different values of pH if both of them are monoprotic acids in the same concentration? rigth?

Well, they simply have different pKas. Both of them are monoprotic acids (they only have one acid hydrogen) but hydrocloric acid is more susceptible of "loosing" it´s acid proton H+. So a solution of hydrocloric acid wolud have bigger concentration of free H+ than an ethanoic acid solution of the same initial concentration. Then the pH of hydrocloric acid solution would be lower.

The reason of why some acids are stronger than others is the molecular structure, it dictates the "easyness" of loosing the proton. When a molecule looses an acid proton it transforms in a negative ion. If the stability of that ion is enhanced by that concrete molecular structure we say that the substance is a strong acid (it looses easily that proton).
 
Hello

Altered-gravity is right. Even very powerful monoprotic acids like HNO3 and HCl have very slight differences in terms of losing proton to solution, but it is very small, so we can omit it and call both as very powerful acids with 100% ionization in nearly all cases (for aqueous systems).

I want to add something to what Altered-gravity said: the less the overall electronegativity of the atom binding hydrogen decreases, the faster the hydrogen is lost. For example, alcohols (alkyl-OH) are weaker acids than thiols (alkyl-SH). HCl is essentially a gas, and used as aqueous solutions by passing this gas from water. Water molecules make hydrogen bonding with chlorine atom by Cl...H bonds, so the overall electronegativity decreases a bit. You may conclude that HCl solution prepared with aprotic solvents having a low dielectric constant has a lower acidity than that with protic, high dielectric-constant-showing solvents. I think this assumption is not wrong.

For acetic acid, the proton is not that free to be lost to water; it is strongly bonded by two very electronegative oxygen atoms. The electronegativity of oxygen is even stronger due to the positive inductive effect of the alkyl group. But when you substitute some hydrogens with electronegative atoms such as chlorine, the acidity increases due to decreasing overall electronegativity of oxygens. But there is a lucky thing that acetic acid molecules prefer to occur as dimers in solution; it makes dissociation easier. So the difference is not very high, higher homologs of acetic acid have very low dissociation constants and it even becomes impossible for them to be dissolved in water for some members.

I hope I did not cause any confusion; for most reasons, Altered-gravity's answer is sufficient. But if you wonder it very much, you will have to go into more detail, mine may help you then.

Regards
chem_tr
 
Thanks altered gravity your answer really helped ,although I am turkish too chem_tr:) your answer caused me some confusion but after i read it more carefully i could understand it .Thanks Guys !
 
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