Explaining Nuclear Fusion to Non-Sci Majors

Agnostic
Messages
110
Reaction score
0
I need to explain fusion to some intro chem people, but they are really dense...Think this will work:





*see picture
 

Attachments

  • bare.PNG
    bare.PNG
    5.8 KB · Views: 573
Physics news on Phys.org
Depending how lay your audience is, this may or may not be too technicall. I would step down just a bit if your audience has not taken Chemistry AP or college level chemistry.
 
Deuterium isn't positively charged, deuterons are. And the strong force isn't restricted to neutrons.
 
Gokul43201 said:
Deuterium isn't positively charged, deuterons are. And the strong force isn't restricted to neutrons.

Right, but Deuterium will be ionized...

Right, but why would it be any relavent at all to talk about it in any other sense? I'm sure I could tell them that it is the interaction between gluons and quarks and go into a whole spill about Quantum Chromodynamics..., but I do think that would be overkill for freshman intro chemistry non science majors.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top