Explaining the Concepts of Force and Energy

AI Thread Summary
The discussion centers on the concepts of work, force, and energy, highlighting a common dilemma where exerting force without movement results in no work done, as defined by physics. A scenario is presented where a person lifts a weight for an extended period, leading to fatigue despite no energy transfer according to the work equation. It is clarified that while the person exerts force, they are not performing external work, and maintaining muscle tension requires internal energy. The conversation also touches on the difference between human exertion and an inanimate object, like a table, which supports weight without tiring. Ultimately, the discussion emphasizes the distinction between internal energy expenditure and the physics definition of work.
HaoPhysics
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1. The dilemma
Work (change in energy) is defined as the exertion of a force over a distance parallel to the force.

So if force is exerted, but nothing is moved (presumably with two immovable objects), then no energy is changed.

But think about the dilemma with a person lifting 100 pounds above his head. He exerts a force of 100 pounds to counter the weight, and say he keeps it above his head for 1 hour. According to the work equation, the person has changed 0 energy in doing this act.

But he has continually exerted a force of 100 pounds for 1 hour, and now he is very tired. But according to work, he has spent 0 energy.

What am I missing?
 
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Another question:

Let there be an object of mass 1 kg in space. There is a constant force F1 acting on the left and F2 acting on the right. F1=F2. The object observes no acceleration. But the object was moving in space at a constant velocity of 1 m/s to the left.

The object moves for 10 seconds.

How much work has F1 done on the object?
 
HaoPhysics said:
1. The dilemma
Work (change in energy) is defined as the exertion of a force over a distance parallel to the force.

So if force is exerted, but nothing is moved (presumably with two immovable objects), then no energy is changed.

But think about the dilemma with a person lifting 100 pounds above his head. He exerts a force of 100 pounds to counter the weight, and say he keeps it above his head for 1 hour. According to the work equation, the person has changed 0 energy in doing this act.

But he has continually exerted a force of 100 pounds for 1 hour, and now he is very tired. But according to work, he has spent 0 energy.

What am I missing?

He's not doing any external work and, if the weight wasn't too heavy, he would only get tired very slowly compared with lifting the weight repeatedly.

But, it takes internal (biomechanical) energy to keep muscles in a locked position, Also, this work is dependent on whether the muscles are in a comfortable position.

If you put the weight on a table, the table wouldn't get tired supporting the weight and wouldn't need a fuel supply.
 
HaoPhysics said:
Another question:

Let there be an object of mass 1 kg in space. There is a constant force F1 acting on the left and F2 acting on the right. F1=F2. The object observes no acceleration. But the object was moving in space at a constant velocity of 1 m/s to the left.

The object moves for 10 seconds.

How much work has F1 done on the object?

I'm sure you can work that out for yourself.
 
PeroK said:
He's not doing any external work and, if the weight wasn't too heavy, he would only get tired very slowly compared with lifting the weight repeatedly.

But, it takes internal (biomechanical) energy to keep muscles in a locked position, Also, this work is dependent on whether the muscles are in a comfortable position.

If you put the weight on a table, the table wouldn't get tired supporting the weight and wouldn't need a fuel supply.

That is true that it is much less tiring than exerting a force greater than 100 pounds to lift it up and down repeatedly. And your point about a table needing fuel makes a lot of sense.
 
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