Explaining the Conservation of Momentum in a Ball-Wall Collision

AI Thread Summary
When a ball collides with a wall, it reverses its momentum from P to -P, resulting in an impulse of -2P. According to the conservation of momentum, the wall must gain 2P, but its large mass means this change is imperceptible. The wall's momentum transfer is effectively absorbed by the building and ultimately the Earth, which has an enormous mass compared to the ball. Therefore, while the wall does gain momentum, the resulting movement is negligible and not observable. This illustrates how conservation of momentum operates in systems with vastly different mass scales.
windwitch
Messages
18
Reaction score
0

Homework Statement


When a ball hits a wall and comes back, it originally had a momentum P. However, when the ball comes back, it has a momentum of -P (as in going in the opposite direction.) According to the law of conservation of momentum, since the ball had an impulse of -2P, the wall must have gained 2P. How do you explain what happened to the 2P since the wall doesn't move?


Homework Equations





The Attempt at a Solution


Just saying, this isn't a homework question or anything so put this question on low priority XD.

I was thinking that the wall does move but because of how large the mass of the wall is compared to the mass of the ball, we just don't perceive a movement. For example, in a building, when a ball hits the wall, the wall gains a momentum of 2P, but since the wall is attached to the building, the building as a whole gains a momentum of 2P, but since the building is attached to the ground, the entire Earth gains a momentum of 2P, etc. and since Earth has an infinitely large mass compared to the ball, there is no change relative to the actual velocity.
 
Physics news on Phys.org
That sounds about right, the actual movement is so small that is it is almost negligible.
 
Thank you very much for answering the questions so quickly XD

(Oh and that signature of yours is brilliant)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top