Exponential Growth in Species A and B: Solving for Initial Grams

AI Thread Summary
Species A and B grow exponentially, with Species A doubling every 2 hours from an initial mass of 6 grams and Species B doubling every 5 hours from 14 grams. The relevant formula for calculating their growth is N = N_0 × 2^(t/T), where N is the final mass, N_0 is the initial mass, t is time, and T is the doubling time. To determine when both species have the same mass, set their growth equations equal to each other and solve for time (t). The discussion highlights confusion around forming the correct equations and understanding the problem's requirements. Ultimately, the goal is to find the time at which both species reach equal mass.
jackleyt
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Homework Statement


Species A doubles every 2 hours and initially there are 6 grams. Species B doubles every 5 hours and initially there are 14 grams.


Homework Equations





The Attempt at a Solution


I've tried graphing this, but I don't think I have the right equations down. I don't know how to form the equations so I can solve the problem.
 
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In general for 'doubling time' problems, we have a simple formula

N = N_0 \times 2^{t \over T}

where N is the number of bacteria after t minutes and T is the time in minutes that it takes to double.

So if that's the relevant equation, attempting a solution should be possible.

EDIT: Although I don't actually know what your question is.
 
Last edited:
jackleyt said:
I don't know how to form the equations so I can solve the problem.

You didn't even say what the problem is.
 
*How long until the species have the same mass? Sorry.
 
jackleyt said:
*How long until the species have the same mass? Sorry.

Okay so you know the equations by which they grow for each of them, and then you set them equal to each other and solve for t.
 
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