Does anyone know how to prove this? exp(jAt)+exp(jBt)= 2exp(j(A+B)/2)cos((A-B)/2)
Jan 20, 2011 #1 hariyo 15 0 Does anyone know how to prove this? exp(jAt)+exp(jBt)= 2exp(j(A+B)/2)cos((A-B)/2)
Jan 20, 2011 #2 hariyo 15 0 Sorry I think i know by now. Here is the solution. exp(jAt)+exp(jBt)= 2exp(j(A+B)/2)cos((A-B)/2) (exp(jAt)+exp(jBt) ) exp(-j(A+B)t/2) exp(+j(A+B)t/2) (exp(j(A-B)t/2)+exp(-j(A-B)t/2) ) exp(+j(A+B)t/2) cos((A-B)t/2) 2exp(j(A+B)/2)t
Sorry I think i know by now. Here is the solution. exp(jAt)+exp(jBt)= 2exp(j(A+B)/2)cos((A-B)/2) (exp(jAt)+exp(jBt) ) exp(-j(A+B)t/2) exp(+j(A+B)t/2) (exp(j(A-B)t/2)+exp(-j(A-B)t/2) ) exp(+j(A+B)t/2) cos((A-B)t/2) 2exp(j(A+B)/2)t