Express cos^6(x) without Powers of Trig Functions

  • Thread starter Thread starter patton_223
  • Start date Start date
AI Thread Summary
To express cos^6(x) without powers of trigonometric functions, it can be rewritten as (cos^2(x))^3, which further simplifies to ((cos(2x) + 1)/2)^3. This expression can be expanded to 1/8 + 3/8 cos(2x) + 3/8 cos^2(2x) + 1/8 cos^3(2x). The challenge remains in eliminating the powers from cos^2(2x) and cos^3(2x). The solution involves applying similar techniques used for cos(2x) to cos(2(2x)).
patton_223
Messages
9
Reaction score
0

Homework Statement


Express cos^6(x) in a form that does not involve powers of trig functions


Homework Equations



idk actually...binomial theorem? algebra? lol


The Attempt at a Solution



ok, so i realized that it can be expressed as (cos^2(x))^3

and that can be ((cos(2x) + 1)/2)^3

and that can be expanded as

1/8+3/8 cos(2 x)+3/8 cos^2(2 x)+1/8 cos^3(2 x)

but how do i get the answer with no powers in in? idk what to do up until that point
 
Physics news on Phys.org
You already showed how to handle cos2(x). Do a similar thing with cos2(2x).
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top