Expressing $\Gamma$(n+$\frac{1}{2}$) for n $\in$ $\mathbb{Z}$ in Factorials

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Homework Statement



Express \Gamma (n+\frac{1}{2}) for n\in\mathbb{Z} in terms of factorials (separately for positive and negative n).

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The Attempt at a Solution



I've got for n\geqslant 0 that \displaystyle \Gamma \left(n+\frac{1}{2} \right) = \frac{(2n-1)!}{2^n} \sqrt{\pi} but what do I do when n<0 ?
 
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The same thing. Use ##n\Gamma(n)=\Gamma(n+1)##, so ##(-1/2)\Gamma(-1/2) = \Gamma(1/2)## and so on.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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