Expression for pressure in a brake system - is this correct?

AI Thread Summary
The discussion focuses on deriving the expression for the force applied to a brake caliper in a hydraulic bicycle braking system. It emphasizes the application of Pascal's law, where pressure is defined as force divided by area. Participants discuss the relationship between the applied force, the distances from the pivot point, and the moments created at both the brake lever and the piston. There is a suggestion to use the formula F = P*A, incorporating the surface area of the pistons, while also addressing the need to calculate moments correctly. The conversation highlights the importance of understanding mechanical advantage in this context.
dreamliner
Messages
16
Reaction score
0

Homework Statement



Write an expression for the force applied to the brake caliper in the braking system(hydraulic) of a bicycle.

F= force applied to the brake lever
a = distance between F and the pivot point of the brake lever.
b= distance between pivot point and lever piston.
d1= diameter of the piston on the brake handle
d2 = diameter of piston on the brake caliper.(PS English is not my mother tongue, so I might have used the wrong words for the different parts of the brake system. I do hope it's possible to understand what I mean.)

Homework Equations



Pascal's law

Force * arm

The Attempt at a Solution



Right away I'm thinking Pascal's law.

My first thought is to write pressure, p, = F1/d1 = F2/d2. I'm a bit unsure about where to incorporate distances a and b.
I'm tempted to use force*arm and write the whole expression as p=(F1*a)/d1 = (F2*b)/d2, but is this correct...?
 
Last edited:
Physics news on Phys.org
You are thinking along the right lines, but you need some more structure to it. Let's start with the forces. The force applied is F; what is its moment about the pivot? What is the moment of the force generated at the piston? How are the two related?
 
Well, working on the assumption that moment force is force *length of the arm the force is working on, the amount about the pivot would be the applied force F*the distance a and the moment at the piston would be F*the distance b.
The relation being that the force F is the same in both cases.

But, that's the same as what I wrote in my initial post so I suspect you might be thinking about something else...?
 
Why would the force at the piston equal F?
 
Indeed. I suspect it's a case of hurrying. "Pascal's law uses F/A. I already have a F in the assignment. Great!".

Would it be correct to use F = P*A where P would be the applied force and A would be the surface area of the pistons, and then multiply the results with the distances?
 
Before doing the hydraulic part, finish the mechanics. You have a lever, with given arms, and a given force applied to one arm. Find the force produced at the other arm.
 
dreamliner said:
Well, working on the assumption that moment force is force *length of the arm the force is working on, the amount about the pivot would be the applied force F*the distance a.

So this part is correct?


I might be about to break some major rules of physics here, but I'm pretty much guessing now... Would the force on the piston be the amount about the pivot* distance b?
 
Back
Top