Extend Vector to Orthogonal Basis

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SUMMARY

To extend a vector to an orthogonal basis in R^3, first identify a vector that is perpendicular to the given vector, such as (1,2,3). This can be achieved using the dot product to ensure orthogonality. Next, apply the cross product to find a third vector that is perpendicular to the first two vectors. The example provided includes the vectors (-5, 1, 1) and (-1, -16, 11) as potential solutions, demonstrating the non-uniqueness of the orthogonal basis extension.

PREREQUISITES
  • Understanding of vector operations, specifically dot product and cross product
  • Familiarity with R^3 vector space concepts
  • Basic knowledge of linear algebra principles
  • Experience with vector notation and manipulation
NEXT STEPS
  • Study the properties of the dot product and its applications in finding orthogonal vectors
  • Learn about the cross product and its role in constructing orthogonal bases in three-dimensional space
  • Explore examples of orthogonal basis extensions in linear algebra textbooks or online resources
  • Practice problems involving vector extensions and orthogonality to reinforce understanding
USEFUL FOR

Students of linear algebra, mathematicians, and anyone interested in understanding vector spaces and orthogonal bases in R^3.

special-g
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How do you extend a vector (let's use vector (1,2,3) for example) to an orthogonal basis for R^3?
 
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special-g said:
How do you extend a vector (let's use vector (1,2,3) for example) to an orthogonal basis for R^3?

First find a vector perpendicular to (1,2,3). That's not hard if you think about the dot product. Any one, there are many. Then find a vector perpendicular to the first two. That's easy in R^3 if you use the cross product. There is no unique answer, you know.
 
Thanks, that helps quite a bit...we just started this material and there aren't very many examples in the book to go off of. :)

I don't know if I did this completely right because I haven't taken calc 3 in a while.

For the first vector, would this be one answer: vector (-5, 1, 1) after taking the dot product.
Then, after taking the cross product of those two vectors, I got vector (-1,-16,11).
 
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