F(x) = x^4 + ax^2 +b. the graph of x has a relative max at 0,1 and

In summary, the equation for F(x) is x^4 + ax^2 + b. The relative max of the graph of x is at the point (0,1). To find the values of a and b, you can plug in the coordinates of the relative max (0,1) into the equation and solve for a and b. The graph of F(x) is a parabola with a relative max at (0,1). The exact shape will depend on the values of a and b. The graph of F(x) is a smooth curve that rises to the relative max at (0,1) and then decreases on either side.
  • #1
meredith
16
0
f(x) = x^4 + ax^2 +b. the graph of x has a relative max at 0,1 and an inflection point at x=1. the values of a and b are...?

ok I am really stuck.
thanks in advance!
 
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  • #2
you have a point on the graph (0,1), when x=0, f(x)=1...you can get one constant.

at a point of inflexion f''(x)=0
 

What is the equation for F(x)?

The equation for F(x) is x^4 + ax^2 + b.

Where is the relative max of the graph of x?

The relative max of the graph of x is at the point (0,1).

How can I find the value of a and b in the equation?

To find the values of a and b, you can plug in the coordinates of the relative max (0,1) into the equation and solve for a and b.

What is the shape of the graph of F(x)?

The graph of F(x) is a parabola with a relative max at (0,1). The exact shape will depend on the values of a and b.

What does the graph of F(x) look like?

The graph of F(x) is a smooth curve that rises to the relative max at (0,1) and then decreases on either side.

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