Factor label method with rotational motion

AI Thread Summary
The discussion centers on calculating the distance traveled on a stationary exercise bicycle based on the wheel's rotational speed and radius. Given a wheel rotating at 8.4 rad/s and a radius of 0.40 m, the circumference is calculated as 2.5 m per revolution. By converting the rotational speed to linear velocity, it is determined that the bike would travel at 21 m/s. Over a duration of 2090 seconds, the total distance covered would be 43,890 meters. This calculation illustrates the application of the factor label method in rotational motion.
wallace13
Messages
31
Reaction score
0
Suppose you are riding a stationary exercise bicycle, and the electronic meter indicates that the wheel is rotating at 8.4 rad/s. The wheel has a radius of 0.40 m. If you ride the bike for 2090 s, how far would you have gone if the bike could move?
w= rad/ sec
2 pi= rev
v= m/s
2pi x r= circumference

.4m x 2pi= 2.5 m/ rev
2.5 m/rev x 8n4 rev/ sec = 21 m/s
21m/s x 2090 s = 43890 m
 
Physics news on Phys.org
wallace13 said:
Suppose you are riding a stationary exercise bicycle, and the electronic meter indicates that the wheel is rotating at 8.4 rad/s. The wheel has a radius of 0.40 m. If you ride the bike for 2090 s, how far would you have gone if the bike could move?

w= rad/ sec
2 pi= rev
v= m/s
2pi x r= circumference

.4m x 2pi= 2.5 m/ rev
2.5 m/rev x 8n4 rev/ sec = 21 m/s
21m/s x 2090 s = 43890 m


8.4 is given in radians / sec. There are 2π radians in a revolution.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top