Factory Power From Total Current

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A small factory operates at 120V/Hz with a total current of 1.2 amperes and a phase angle of 2.1 radians. The real power dissipated can be calculated using the formula P = Vrms x Irms x pf, where pf is the power factor derived from the phase angle. Concerns were raised about the realism of a 1.2A current, suggesting it is more typical for small light bulbs rather than heavy machinery. The phase angle's conversion to degrees was questioned, with clarification that it should fall between 0 and -90 degrees, indicating potential power generation if it exceeds this range. The discussion highlights the importance of verifying electrical parameters in practical scenarios.
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1.A small factory utilizes the standard 120V/Hz voltage. When all the heavy machinery is operational, the total electric current flowing into the factory is 1.2 amperes. The phase angle between the voltage and current waveforms is measured to be 2.1 radians. Find the real power dissipated by the factory. Round off your answer to two decimal places.



2. P = Vrms x Irms x pf



3.Vrms = 120, Irms = 1.2?, I converted 2.1 to degrees and got 120.321. I thought it would just be 120 x 1.2 x cos(120.321).
 
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Are you sure you have these figures correct? A current of 1.2A is unrealistic. That's the current for a pair of small light globes.

The phase angle should lie between 0 and -90 degrees. If it indeed is -120 degrees, this implies that the factory is generating power.

Is this likely to be a trick question?
 
From your identical thread: that 1.2A can be assumed to be RMS, that's how AC quantities are usually specified (by default).
 

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