Failing physics in dire need of help. PLEASE

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    Failing Physics
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To solve the problem of net work done on the wheelbarrow, first calculate the work done by the worker using the formula W = Fd, where F is the applied force and d is the distance. The worker applies a force of 50.0N over a distance of 5.0m, resulting in positive work of 250J. The frictional force of 43N acts in the opposite direction, contributing negative work of -215J over the same distance. The net work is then the sum of the positive and negative work, which equals 35J. Understanding the signs of the forces is crucial for accurately determining the net work.
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A worker pushes a wheelbarrow with a horizontal force of 50.0N over a level distance of 5.0m. If a frictional force of 43N acts on the wheelbarrow in a direction opposite to that of the worker, what net work is done on the wheelbarrow?

how would i go about solving this problem?
 
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The force applied by the worker is constant and along the direction of displacement and the force done by friction is opposite the direction of displacement so we can use the relation

W = Fd

The net work is the sum of all the works (watch your signs!).
 
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