arul_k
Hello,
I was reading about Faradays rotating disk paradox wherein when both the copper disk and magnet are rotated together an eddy current is induced along the radius of the copper disk. My question is if a maganitized steel disk (with one side being the N pole and the other side being the S pole) is rotated on its axis would a current be induced along its radius just as it is induced in the copper disk mentioned above?

Bob S
This an interesting and important question in the generation of potentials and currents in moving conducting objects in magnetic fields. First, if a conducting disk freely rotates about an axis parallel to a uniform magnetic field, there is a radial electric potential (but no current) induced in the conducting disk. The disk rotates without eddy current generation, and no eddy current losses. But if an external stationary electric circuit is completed between the axle and outer rim of the rotating disk, then there is a current. Homopolar generators are based on this effect. See
http://en.wikipedia.org/wiki/Homopolar_generator
This not specifically an "eddy current" in a spacially varying magnetic field, but the radial Lorentz force F = q(v x B) produced by an azimuthally moving conductor in an axial magnetic field.
In the situation proposed in the OP, the disk is both magnetized and rotating. There is a current, as long as the rim contact is stationary.

zoobyshoe
Hello,
I was reading about Faradays rotating disk paradox wherein when both the copper disk and magnet are rotated together an eddy current is induced along the radius of the copper disk.
This is a confusing illusion. The field lines of the magnet, which curl around in space to the back end of the magnet, are rotating with the magnet and inducing current in the wire that's being used to contact the rotating disk. There is no current actually being induced in the rotating disk, just in the stationary wire.

arul_k
Thanks for the replies.

In the situation proposed in the OP, the disk is both magnetized and rotating. There is a current, as long as the rim contact is stationary
.

So I presume this current could be measured with a galvanometer. Do you know if this has been experimentally verified?

This is a confusing illusion. The field lines of the magnet, which curl around in space to the back end of the magnet, are rotating with the magnet and inducing current in the wire that's being used to contact the rotating disk. There is no current actually being induced in the rotating disk, just in the stationary wire.

But there is also the opnion that the field is independent of the magnet and remains stationary. I guess that's why it remains a paradox. Considering that the field has no mass or matter how exactly would you define the "rotation" of a uniform field ie what is it that is actually rotating?

zoobyshoe
But there is also the opnion that the field is independent of the magnet and remains stationary. I guess that's why it remains a paradox.
The illusion the field remains stationary comes from the assumption the current is induced in the disk. Once you realize the current is induced in the wire the paradox disappears.
Considering that the field has no mass or matter how exactly would you define the "rotation" of a uniform field ie what is it that is actually rotating?
How is the same problem solved for "translation" of the field when a magnet is moved in and out of a coil?

Bob S
How is the same problem solved for "translation" of the field when a magnet is moved in and out of a coil?
The misconception here I think is that the voltage and current (when there is a rim contact) is based on the Faraday induction principle. It is not. This is actually based on the Lorentz force principle, which does not require a time derivative (e.g., dB/dt). It requires a velocity perpendicular to the B field. A suble clue is that the polarity of the voltage (and direction of the current) does not change when the direction of rotation of the disk is reversed. See
http://en.wikipedia.org/wiki/Homopolar_generator

zoobyshoe
The misconception here I think is that the voltage and current (when there is a rim contact) is based on the Faraday induction principle. It is not. This is actually based on the Lorentz force principle, which does not require a time derivative (e.g., dB/dt). It requires a velocity perpendicular to the B field. A suble clue is that the polarity of the voltage (and direction of the current) does not change when the direction of rotation of the disk is reversed. See
http://en.wikipedia.org/wiki/Homopolar_generator
That wikipedia article references the DePalma N-Machine:

* Barlow's Wheel
* Electric generator
* Electric motor
* List of homopolar generator patents
* Homopolar motor
* Bruce De Palma

and:

Thomas Valone, The Homopolar Handbook : A Definitive Guide to Faraday Disk and N-Machine Technologies. Washington, DC, U.S.A.: Integrity Research Institute, 2001. ISBN 0-9641070-1-5

The N-Machine is a "free energy" device, i.e. crackpot technology:

http://antigravitypower.tripod.com/FreeEnergy/depalma.html

That wiki article is completely untrustworthy.

Bob S
That wikipedia article references the DePalma N-Machine:
and:
The N-Machine is a "free energy" device, i.e. crackpot technology:
http://antigravitypower.tripod.com/FreeEnergy/depalma.html
That wiki article is completely untrustworthy.
It is unfortunate that one reference in the Wiki article to the DePalma machine tainted the entire article. Here is another old paper on the Canberra accelerator project, including the homopolar generator:
http://physics.anu.edu.au/History/fire_in_the_belly/Fire_in_the_Belly03.pdf [Broken]
which shows several photos of the Canberra homopolar generator with a man standing beside it (see page 30 of article (page 10 of pdf)). This unit generated over 2 million amps for pulses up to 10 seconds. Read article for details.

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arul_k
The illusion the field remains stationary comes from the assumption the current is induced in the disk. Once you realize the current is induced in the wire the paradox disappears

How would you then explain the case where no current is generated in the disk when the magnet is rotated?

How is the same problem solved for "translation" of the field when a magnet is moved in and out of a coil?

Obviously any physical displacement of the magnet will cause the "magnetic effect" or field to move along with it. How ever that does not imply that the field rotates when the magnet is rotated about its polar axis.

zoobyshoe
How would you then explain the case where no current is generated in the disk when the magnet is rotated?
I assume you mean stationary disc, rotating magnet. The field lines emerge from the pole of the magnet, go through the disc, curl around, and come back and cut the wire going in the opposite direction. The direction of the current generated in the wire opposes the direction of the current generated in the disc and they cancel each other out.