- #1

hagobarcos

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## Homework Statement

A student of weight 667 N rides a steadily rotating Ferris wheel. At the highest point, the magnitude of the normal force on the student from the seat is 556 N.

**a)**Does the student feel "light" or "heavy" there?

**b)**What is the magnitude of Fn at the lowest point?

**c)**If the wheel's speed is doubled, what is the Fn at the highest point,

**d)**and at the lowest point?

## Homework Equations

**Fc = m(v²/R)**

**Ac = (v²/R)**

Fnet = m a

## The Attempt at a Solution

Okay this is where I am a bit backwards:

At the top:

Fnet = may

Fn-Fc-mg = may = 0

^^ I think this part is wrong,

I also attempted it like this:

Fn -mg = Fc (Since rotating in a circle, some acceleration due to rotation)

Fn = mg + Fc

570 N = 667 N + Fc

Fc at top = -111 Newtons

So since the seat is being pulled downward, and the normal force is less than the full gravitational force, the student should feel lighter than normal.

at the bottom:

Okay here is where I really get messed up:

Fn -mg = Fc

Fc is now +111 N, still pointing towards the center of the circle.

Fn = mg + Fc = 667 N + 111 N = 778 N.

Now, when the wheel's speed is doubled, how do I calculate the new centripetal force?

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