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Fibonacci recurance relation

  • Thread starter morbello
  • Start date
i have to find the recurrence relation to express both f[tex]_{n+1}[/tex] and f[tex]_{n}[/tex] with f[tex]_{n+2}[/tex] and f[tex]_{n+3}[/tex]

my answer is
f[tex]_{n+1}[/tex]+f[tex]_{n+2}[/tex]+f[tex]_{n+3}[/tex].....f[tex]_{n}[/tex]

ive got other ways off doing it in the book but they do not use f[tex]_{n+3}[/tex]

these are

f[tex]_{n+2}[/tex]+f[tex]_{f-1}[/tex]-f[tex]_{n}[/tex]


they all should be in lower case but i can not seam to get the post to do it i hope it does not make it hard to help me with the question.



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lanedance

Homework Helper
3,304
2
hi morbello

you can click on any latex code to see how it is typed, easiest to put tex quotes around your whole equation


but I'm not too sure what you're trying to do... ;) shouldn't you have an equals sign somewhere?

something like
[tex] f^{n+1} = f(n+1) = f(n) + ...?[/tex]
 

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