Fick's First Law (Diffusion Problem)

AI Thread Summary
A sheet of MgO, 0.05 cm thick, separates layers of Ni and Ta to prevent their reaction at 1400 ºC, where Ni ions diffuse through the MgO. The diffusion coefficient for nickel ions in MgO is 9*10^(-12) cm²/s, and the lattice constant of Ni is 3.6*10^(-8) cm. The main challenge is calculating the concentration gradient needed for Fick's First Law, given that there are no Ni ions in the MgO. This scenario assumes an unsteady-state situation, with the Ni concentration at the Ta side of the MgO being zero. Understanding these parameters is crucial for determining the diffusion rate of Ni ions through the MgO.
goncalo x. r.
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1. A sheet (with a thickness of 0.05 cm) of MgO lies in between layers of Ni and Ta to avoid reaction between these two metals . At 1400 ºC, ions of Ni are created and diffuse through the ceramic MgO to the Ta. Find the number of ions that go through the MgO per second, knowing that the diffusion coefficient of the nickel ions in the MgO is 9*10^(-12) (cm^2)/s, and the lattice constant of Ni at 1400 ºC is 3.6*10^(-8) cm.

Homework Equations


Fick's First Law: J=-D*gradient(n) , n being the concentration of the species in cause

The Attempt at a Solution


The exercise is pretty straight forward. The real issue is to calculate the gradient. With the lattice constant and Ni's type of structure (FCC) it's easy to find Ni's concentration, but I am lacking another concentration to make the gradient. Is the 'ceramic' suppose to imply some lattice constant and/or type of structure?
(All the information given is highlighted)

Thanks in advance,
Gonçalo X. R. N.
 
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The thickness of the MgO sheet is given. Assume that there are no Ni ions in the MgO.
 
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Oh ok, didn't think of that assumption.
Thank you!
 
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If you assume there are no Ni ions in the MgO, you have an unsteady-state situation. I would assume you are looking for the steady-state diffusion rate and that the Ta reacts instantly with the Ni so that the Ni concentration at the Ta side of the MgO is zero.
 
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Thank you!
 
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