Figuring out time when you have acceleration and distance.

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To determine the time it takes for a car to travel 30.0 meters with an acceleration of 2.00 m/s², it is assumed that the car starts from rest (initial velocity vi = 0 m/s). The relevant formula for distance under constant acceleration is d = 1/2 at². Rearranging this to solve for time t results in t = √(2d/a). Substituting the values gives t = √(2 * 30.0 m / 2.00 m/s²), leading to the final calculation of time.
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How long does it take a car to travel 30.0m if it accelerates at a rate of 2.00m/s^2?
Given
Distance- 30.0m
A-2.00m/s^2

Do I need to find vi?
 
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You must need to assume it is initially at rest, otherwise the problem is incomplete.
 
1MileCrash said:
You must need to assume it is initially at rest, otherwise the problem is incomplete.

So now I have
Distance- 30.0m
a-2.00m/s^2
vi-0m/s
So can i now use the d=1/2at^2 formula?
But we're solving for t
making the equation t, taking the square root of 2d/a right?
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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