Final temperature in reversible expansion

AI Thread Summary
The discussion focuses on calculating the final temperature, total heat transferred, and total entropy change for a reversible expansion of an ideal monatomic gas. The final temperature is derived as 1000(a/b)^(2/3). The total heat transferred to the gas is expressed as 1000Rln(a) + 1000R(a/b)^(2/3)ln(c/b). The total entropy change is calculated using the formula Rln(ac/b). The calculations provided appear to be correct based on the initial conditions and equations given.
twinklestar28
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Homework Statement



One mole of an ideal monatomic gas initially at volume Vi and temperature 1000k expands to a final volume Cvi in three reversible steps: 1) isothermal expansion from Vi to aVi, 2) adiabatic expansion from aVi to bVi and 3) isothermal expansion from bVi to Cvi

In terms of a,b,c calculate
a) final temperature
b) total heat transferred to gas
c) total entropy change


Homework Equations



TV^γ-1=C
Q=nrtln(V1V2)
ds= dq/dt


The Attempt at a Solution



a) final temperature = 1000(a/b)^2/3

b) heat transferred = 1000Rlna + 1000R(a/b)^2/3ln(c/b)

c) entropy change = Rln(ac/b)

Could someone check these for me please?
 
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Your answers look correct to me.
 
ok thanks alot
 
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