Final Temperature of Copper-Water System

AI Thread Summary
To find the final temperature of a copper-water system, apply the principle of conservation of energy where heat lost by copper equals heat gained by water and the vessel. Use the formula q = c x mass x change in temperature for both the copper and water, treating them as separate systems but sharing the final temperature. The heat capacity of the vessel can be combined with the water's heat capacity for a total heat capacity, simplifying calculations. The final temperature is determined by solving the equations simultaneously. This approach ensures accurate results for the thermal equilibrium of the system.
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Homework Statement


A 505g piece of copper tubing is heated to 99.9 degrees C and placed in an insulated vessel containing 59.8g of water at 24.8 degrees C. Assuming no loss of water and a heat capacity for the vessel of 10.0 J/K, what is the final temperature of the system? (c of coppuer is 0.387 J/(gk))


Homework Equations



q = c x mass x change in temperature
change in termperature = T[final] - T[initial]

The Attempt at a Solution


I have no idea how to go about solving this problem
 
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Heat lost = heat gained.
 
how do you account for the two separate systems combining into one?
(i.e. how would you deal with the two different masses?)
 
Treat heat gained/lost separately. Use equation you have already posted for each mass separately. The only commong thing in both equations will be the final temperature, and that's what you will solve for.
 
how do you incorporate the heat capacity of the vessel?
 
Combine it with water (simply add them, nothing more fancy). It coul be given as vessel mass and specific heat, but the heat capacity is the same, just details are hidden - which completely doesn't matter.
 
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