Find 3rd Component of Y Velocity for Projectile Question

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To find the third component of the Y velocity for a projectile launched at 13.5 m/s at 24 degrees, the initial vertical velocity is 5.5 m/s, while the final vertical velocity will be equal in magnitude but opposite in direction due to gravity. The discussion emphasizes the importance of understanding kinematic equations for projectile motion rather than relying solely on calculator programs. Participants suggest that the user may have misallocated values in their calculations. The conversation highlights the need for a solid grasp of the principles of projectile motion to solve related problems effectively. Understanding these concepts will facilitate accurate calculations for time in the air and horizontal distance traveled.
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A cannon ball is fired from a catapult at 13.5 m/s at 24 degrees above the horizontal.
a. How long is it in the air?
b. What is the horizontal component of the velocity?
c. How far from the catapult does the ball land?

I used a program on my calculator that we are allowed to use and got the X Magnitude to be 12.3 and the Y Mag. to be 5.5..with that i filled in this chart:

vX 12.3
dX
t

vfY 5.5
voY
dY
t
aY -9.8

i need a third component in the Y column, then i can figure out how to do the rest. How would I go about finding it?
 
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You really shouldn't need to use a program on your calculator. I think it rather defeats the object of learning about projectiles. Have you been taught the kinematic equations? They can be found in this thread: https://www.physicsforums.com/showthread.php?t=110015

You should be able to work out everything given these and hopefully understand projectile motion better.
 
yeah we weren't taught that..

but I am thinking that what i may have done is but the 5.5 in the wrong spot? or should the original velocity be zero?
 
The original speed in the y direction will be 5.5 ms-1. The final speed will be the same but in the opposite direction.
 

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