Find a linearly independent subset F of E

csc2iffy
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Homework Statement


Let U be the subspace of R5 spanned by the vectors
E={(1,1,0,0,1),(1,1,0,1,1),(0,1,1,1,1),(2,1,-1,0,1)}.
Find a linearly independent subset F of E with Span(E)=U


Homework Equations





The Attempt at a Solution


I figured out that E is linearly dependent and that the solution set to it is
c1=-t, c2=-t, c3=t, c4=t
I'm not sure how to figure out which vectors are linear combos of the each other??
I'm assuming that once I find the linearly dependent one(s), then the remaining vectors will be linearly independent. Will this be F?
 
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please please PLEASE help me someone, I have a final on this at 8AM :(
 
csc2iffy said:

Homework Statement


Let U be the subspace of R5 spanned by the vectors
E={(1,1,0,0,1),(1,1,0,1,1),(0,1,1,1,1),(2,1,-1,0,1)}.
Find a linearly independent subset F of E with Span(E)=U


Homework Equations





The Attempt at a Solution


I figured out that E is linearly dependent and that the solution set to it is
c1=-t, c2=-t, c3=t, c4=t
I'm not sure how to figure out which vectors are linear combos of the each other??
I'm assuming that once I find the linearly dependent one(s), then the remaining vectors will be linearly independent. Will this be F?

From your work, the vectors in E are linearly dependent. If you set t = 1, you have -1v1 + (-1)v2 + 1v3 + 1v4 = 0, where the vi vectors are the ones in your set.

This equation can be solved for v4 as a linear combination of the other three, so you can discard v4. If the resulting set is now linearly independent, then that's your answer. If the resulting set is still linearly dependent, keep discarding vectors until you get a set of vectors that is linearly independent.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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