Find a particular solution for a non-homogeneous differential equation

blouqu6
Messages
3
Reaction score
0
Find a particular solution for the following equation:

y"+2y'+y=12.5e-t

I'm not sure on which method to use. Here's my attempt using the undetermined coefficients method:

→y"+2y'+y=12.5e-t
r2+2r+1=0
r=-1 *not even sure if this part is useful

→yp=e-t
yp'=-e-t
yp"=e-t

→y"+2y'+y=12.5e-t
(e-t)+2(-e-t)+(e-t)=12.5e-t

e-t(1-2+1)=e-t(12.5)

This is where I get stuck; I don't believe I'm taking the right approach from the get-go. Any help would be greatly appreciated.
 
Physics news on Phys.org
blouqu6 said:
Find a particular solution for the following equation:

y"+2y'+y=12.5e-t

I'm not sure on which method to use. Here's my attempt using the undetermined coefficients method:

→y"+2y'+y=12.5e-t
r2+2r+1=0
r=-1 *not even sure if this part is useful
It's very useful, as it gives you the complementary solution, the solution to the homogeneous problem. Note that r = -1 is a repeated solution of the characteristic equation.
blouqu6 said:
→yp=e-t
Not a good choice for a particular solution. e-t is a solution of the homogeneous problem, so can't possibly be a solution of the nonhomogeneous problem.
blouqu6 said:
yp'=-e-t
yp"=e-t

→y"+2y'+y=12.5e-t
(e-t)+2(-e-t)+(e-t)=12.5e-t

e-t(1-2+1)=e-t(12.5)

This is where I get stuck; I don't believe I'm taking the right approach from the get-go. Any help would be greatly appreciated.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top