Find all real and complex zeros of h(x)

  • Thread starter Thread starter FrugalIntelle
  • Start date Start date
  • Tags Tags
    Complex
AI Thread Summary
To find the real and complex zeros of the function x^3 + 2x^2 - 16, users suggest starting with the Rational Root Theorem, which identifies potential rational roots as factors of -16. One participant attempted to factor the polynomial but struggled after the initial steps. It is recommended to express the polynomial in the form (x - r)(x^2 + lower degree terms) to facilitate finding roots. Additionally, reviewing textbook examples related to similar problems may provide further insights.
FrugalIntelle
Messages
6
Reaction score
0

Homework Statement


It's asking me to find all the real and complex zeros of the function x^3 + 2x^2 - 16.


Homework Equations





The Attempt at a Solution


I have tried factoring the first 2 terms and i come up with x2(x+2) - 16 but I don't know where to go from there. Any help would be appreciated.
 
Physics news on Phys.org
FrugalIntelle said:

Homework Statement


It's asking me to find all the real and complex zeros of the function x^3 + 2x^2 - 16.


Homework Equations





The Attempt at a Solution


I have tried factoring the first 2 terms and i come up with x2(x+2) - 16 but I don't know where to go from there. Any help would be appreciated.

This is not really a very good start. Instead you should see if you can find a number r such that x3 + 2x2 - 16 = (x - r) * (x2 + lower degree terms).

The Rational Root Theorem (you can search for this on the web) says that if r is a root of your cubic polynomial, it has to be a number that evenly divides -16. The only candidates are ±1, ±2, ±4, ±8, and ±16. Does your textbook mention this theorem? Does your textbook show any examples of similar problems? Do you read your textbook?
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...
Back
Top