Can the Roots of x^4 + 7x^2 + 6 = 0 be Imaginary?

[Dustinsfl]

x^4 + 7x^2 + 6 =0

I know the answers are imaginary but I don't remember how to solve this equation.

 

[boboYO]

Let t=x^2 and solve for t. Then once you have t, you can easily find x.

 

[Dustinsfl]

If I do that and solve for t, I obtain two real solutions when all 4 all imaginary.

 

[boboYO]

using quadratic formula:

x^2=\frac{-7\pm \sqrt{49-24}}{2}
x^2=\{-6,-1\}

both values of x^2 for negative, so all 4 values of x are imaginary. Check your working?