Find Angular Velocity of Centrifuge with Particle 10.0 cm Away

AI Thread Summary
The discussion focuses on calculating the angular velocity of a centrifuge with a particle located 10.0 cm from the axis, experiencing a radial acceleration of 1.00*10^3 times gravitational acceleration. The correct radius is established as 0.01 m, leading to the equation 1.00*10^3*9.80 = (0.01)w^2. Upon solving, the angular velocity is calculated to be approximately 989 rad/sec. A clarification is made regarding the conversion of centimeters to meters, emphasizing the importance of accurate unit conversion. The final answer provided is 313 rad/sec, indicating a potential error in the initial calculation.
Miike012
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A centrifuge is used to increase the sedimentation rate of
particles suspended in a liquid, over the rate produced
by gravity alone. Find the angular velocity of a centri -
fuge in which a particle 10.0 cm from the axis of rotation
experiences a radial acceleration of 1.00* 10^3
times gravitational acceleration g.

Solution: radius (r) = 0.01 m ; ar = 1.00*10^3*9.80


1.00*10^3*9.80 = (.01)w^2

w = ( 1.00*10^3*9.80/.01)^(1/2) = 989

Answer is 313 rad/sec...

where did I go wrong>?
 
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10.0 cm = 0.1 m

Do not underestimate the girth of the centimeter.
 
thank you,
 
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