Find critical point of interval problem

tronter
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Can you just say that x(4-x) <4 for x \in (0,2)? You don't need to prove this?

Or to prove this, just find critical point which is x = 2?
 
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Two ways - you can choose.
1) Find the places where the left side is zero, pick a value of x from each of the portions of the number line, and check whether the (left side - 4) is positive or negative at each location.
2) Note that in (0,2) both factors on the left are smaller than two, so...
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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