Find current for circuit with capacitor, resistor, capacitor in series

AI Thread Summary
To solve the circuit problem involving two capacitors and a resistor in series, the initial approach used Kirchhoff's Voltage Law (KVL) to derive the current function over time. The equations were simplified to show a relationship between the current and the derivatives, but an inconsistency arose due to both capacitors having the same value, leading to an incorrect equivalent resistance. The discussion suggests reconsidering the signs of one capacitor or adjusting the combined capacitance to 0.5uF to align with the passive configuration. This highlights the importance of correctly accounting for the configuration and values of circuit components in calculations.
Cyrus
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I have to solve this problem for a circuit. Its a capacitor, a resistor and another capacitor all in series.

Both capacitances are the same, 1uF, and the resistor is 100k-Ohm.

I have to find the current function of time.

What I did was use KVL to get:


- \frac{1}{c_1} \int i(t)dt + v_1 (t_0) + \frac{1}{c_2} \int i(t)dt + v_2 (t_0) + R i(t) = 0

Then I took the derivative to get:

- \frac{1}{c_1} i(t) + R \frac {di}{dt} + \frac{1}{c_2}i(t) =0

Which simplifies to:

R( \frac{1}{c_2} - \frac {1}{c_1} )^{-1} \frac {di}{dt} +i(t) = 0

But the two capacitances have the same value, which means that RC-eq is zero. That's wrong...hmmmmmmmmm
 
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WTF. Why not change the signs of one of the capacitances. They should have the same sign. Or just let the combined capacitance equal to .5uF.
 
Because based on the diagram, they are in the passive configuration which is why it is negative.
 
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