- #1
mark8623
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URGENT! Find exact length of curve!
Sorry I don't know how to type the integral symbol... But here is the question!
A curve is given by x= the integral from 0 to y of [(9t2+6t)^1/2] dt for 1< y < 5. Find the exact length of the curve analytically by antidifferentiation.
The length of a curve equation is th integral from a to b of the square root of [1+ (dy/dx)2]
I know that the derivative of the integral of the curve is equal to [9y2+6y], becuase of the fundamental theorum of calculus. Then I find the derivative of that which is 18y+6, and I plugged it into the curve length equation. But when I tried putting it into my calculator it had a domain error... why!?
All help is appreciated, I need to know this for my mid term tomorrow. Thank you!
Homework Statement
Sorry I don't know how to type the integral symbol... But here is the question!
A curve is given by x= the integral from 0 to y of [(9t2+6t)^1/2] dt for 1< y < 5. Find the exact length of the curve analytically by antidifferentiation.
Homework Equations
The length of a curve equation is th integral from a to b of the square root of [1+ (dy/dx)2]
The Attempt at a Solution
I know that the derivative of the integral of the curve is equal to [9y2+6y], becuase of the fundamental theorum of calculus. Then I find the derivative of that which is 18y+6, and I plugged it into the curve length equation. But when I tried putting it into my calculator it had a domain error... why!?
All help is appreciated, I need to know this for my mid term tomorrow. Thank you!