Find Explicit Expression for f^-1(x) in f(x)=\frac{-2x}{3x-4}

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For the function f given by the equation f(x)=\frac{-2x}{3x-4}, determine where the relation f^-1 is a function. If f^-1 is a function, write an explicit expression for f^-1(x).

Need help writing explicit expression. Any guidance?
 
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You have to check if the given function is invertible or not.If it is one-one and onto then it is invertible and f^-1 is a function or it exists.
I don't get you , when you say 'explicit function'.You mean the inverse?
 
You first say "determine where the relation f-1 is a function" which implies that f-1 is a function for some values of x, not others. But then you say "If f-1 is a function". Are you sure it wasn't "determine whether the relation f-1 is a function?

Let y= \frac{-2x}{3x-4} and "swap" x and y:
x= \frac{-2y}{3y-4}[/itex]<br /> Now can you solve that for y? If so, f<sup>-1</sup> exists and you have found it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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