Find f'(5) for f(x)=g(h(x)) & [g(x)]3

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Homework Statement


Let
g(5)=-3
g'(5)=6
h(5)=3
h'(5)=-2

Find f'(5) for f(x)=g(h(x))
Find f'(5) for [g(x)]3

The Attempt at a Solution


Find f'(5) for f(x)=g(h(x))
g'(h(x))*h'(x)
g'(3)*-2

But I don't know where to go from there because I'm not given g'(3).

Find f'(5) for [g(x)]3
I was thinking just to use the power rule, but it wasn't right
3g(x)2
3(-3)2
 
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DollarBill said:

Homework Statement


Let
g(5)=-3
g'(5)=6
h(5)=3
h'(5)=-2

Find f'(5) for f(x)=g(h(x))
Find f'(5) for [g(x)]3

The Attempt at a Solution


Find f'(5) for f(x)=g(h(x))
g'(h(x))*h'(x)
g'(3)*-2

But I don't know where to go from there because I'm not given g'(3).

Find f'(5) for [g(x)]3
I was thinking just to use the power rule, but it wasn't right
3g(x)2
3(-3)2
You had the right idea, but you lost you equation, and so lost your way.
  1. Start with the equation for f(x). f(x) = ...
  2. Find f'(x). This should be an equation. f'(x) = ...
  3. Evaluate f' at x = 5. f'(5) = ... To do this, you'll need the function values in your problem statement.
Mark
 
For the second one think of it like any ordinary chain rule problem. [g(x)]^3 = h(g(x)) where h(x) = x^3.
 
Mark44 said:
You had the right idea, but you lost you equation, and so lost your way.
  1. Start with the equation for f(x). f(x) = ...
  2. Find f'(x). This should be an equation. f'(x) = ...
  3. Evaluate f' at x = 5. f'(5) = ... To do this, you'll need the function values in your problem statement.
Mark
I'm actually not quite sure what you mean...

1. Start with equation: f(x)=(g(h(x))
2 Find f'(x): f'(x)=g'(h(x))*h'(x)
3.f'(5)=g'(h(5))*h'(5)
4.f'(5)=g'(3)*-2

And I'm pretty much where I was before...
 
SticksandStones said:
For the second one think of it like any ordinary chain rule problem. [g(x)]^3 = h(g(x)) where h(x) = x^3.
Didn't see your reply before. Thanks, but I'm still not sure about the first one.

I'm always wary of going with a "None of the above" type answer.
 
DollarBill said:
I'm actually not quite sure what you mean...

1. Start with equation: f(x)=(g(h(x))
2 Find f'(x): f'(x)=g'(h(x))*h'(x)
3.f'(5)=g'(h(5))*h'(5)
4.f'(5)=g'(3)*-2

And I'm pretty much where I was before...
Not really. You have an expression for f'(5). Take another look at the information that was given in the problem to make sure you have all of the given information and that you have included it in this thread. If so, and the problem didn't give you a value for g'(3), then you have done everything that you can and -2*g'(3) is the value for f'(5).
Mark
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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