Find Final Temperature of Iron & Water in Thermal Equilibrium

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To determine the final temperature of a 67.1 g piece of iron heated to 64.7 °C when placed in 77.5 mL of water at 15.8 °C, the principle of heat transfer is applied, where heat gained by water equals heat lost by iron. The specific heat capacities of both substances are crucial for calculations. The formula for calorimetry, which involves the specific heat capacity, mass, and temperature change, is essential for solving the problem. The discussion highlights confusion regarding the variables used in the heat transfer equation, specifically the terms "n" and "T," and emphasizes the need for clarity on units and the relationship between them to properly calculate heat energy.
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A piece of iron weighing 67.1 g is heated to 64.7 oC and dropped into a beaker containing 77.5 mL of water at a temperature of 15.8 oC. What is the final centigrade temperature of iron and water after they come to thermal equilibrium?


i tried doing it by doing

n3t3=n1t1+n2t2 and it didnt work, please help

I know heat gained= heat lost, and the final value of T should be same for both iron and water, since they are in equilibrium.
 
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Do you know the formulas of calorimetry??

Daniel.
 
ya you need to know the specific heats of each one of the substances.
 
parwana said:
A piece of iron weighing 67.1 g is heated to 64.7 oC and dropped into a beaker containing 77.5 mL of water at a temperature of 15.8 oC. What is the final centigrade temperature of iron and water after they come to thermal equilibrium?


i tried doing it by doing

n3t3=n1t1+n2t2 and it didnt work, please help

I know heat gained= heat lost, and the final value of T should be same for both iron and water, since they are in equilibrium.

What are n and T ? What are their units ? If you multiply them, do you get something that has units of heat/energy ? If not, what are you missing ?
 

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