1. The problem statement, all variables and given/known data A chain consisting of five links, each of mass 0.105 kg, is lifted vertically with a constant acceleration of a = 3.5 m/s2. Find the magnitude of the force that link 3 exerts on link 2. 2. Relevant equations F = ma 3. The attempt at a solution I did: F = ma FU - (0.105 * 3)(9.8) = (0.105) * 3.5 FU = 4.19 N where FU is the force pulling up, (0.105*3) is the mass of the link's 5, 4, and 3 weighing down on link 2 (mg=weight) and then the mass*accel on the other side. This is wrong. why? and how do i get the right answer?