Find initial velocity of the spaceship

AI Thread Summary
To find the initial velocity V0 of a spaceship given its acceleration function a(t) = 3 m/s² - (2 m/s³)t, integration is necessary. The velocity function is derived as v(t) = 3t - t² + V0. Further integration leads to the position function z(t) = (3/2)t² - (1/3)t³ + V0t + z0. Setting the position at t=5 seconds equal to the initial position results in the equation 0 = 37.5 - 41.7 + 5V0. Solving this gives the initial velocity V0 as 0.84 m/s.
TyFelmingham
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a) The acceleration of a spaceship is given by a(t) = 3 m/s2 – (2 m/s3 ) t. Find the initial velocity V0 so that the spaceship is at the same point where it started after 5 seconds.

No idea how to do this one, but do you need to integrate?

Ty
 
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Yes you will have to integrate.
 
PhysicsMajor said:
Yes you will have to integrate.
How do you integrate that?
 
TyFelmingham said:
a) The acceleration of a spaceship is given by a(t) = 3 m/s2 – (2 m/s3 ) t. Find the initial velocity V0 so that the spaceship is at the same point where it started after 5 seconds.

No idea how to do this one, but do you need to integrate?

Ty
a(t) = (dv/dt) = 3 - 2t ::: ⇒ v(t) = ∫ (3 - 2t) dt = 3t - t2 + v0
v(t) = (dz/dt) = 3t - t2 + v0 ::: ⇒ z(t) = ∫ (3t - t2 + v0) dt = 3t2/2 - t3/3 + v0t + z0

Problem requires that {z(5) = z0}, so that:
z(5) = z0 = 3(5)2/2 - (5)3/3 + v0(5) + z0
⇒ 0 = (37.5) - (41.7) + 5v0
⇒ 5v0 = 4.2
⇒ v0 = (0.84 m/sec)


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