Find Integral of sqrt(e^(9x)) - Incorrect Solution Explained

[7yler]

Find the integral.
$$\int\sqrt{e^{9x}} dx$$

I figured that $$\int\sqrt{e^{9x}} dx$$ is equal to $$\int(e^{9x/2}) dx$$ so the integral should simply be $$e^{9x/2}+C$$

Why isn't this correct?

 

[lineintegral1]

Take the derivative of your answer and you'll see what you left out. Almost got it.

 

[7yler]

2/9! Thanks a ton.