Find Magnitude of FA & FB in 8.27 kg Object

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To find the magnitudes of forces FA and FB acting on an 8.27 kg object, two scenarios are analyzed. In the first scenario, both forces point east, resulting in an acceleration of 0.57 m/s². In the second scenario, FA points east and FB points west, leading to an acceleration of 0.35 m/s². The net force equations for both cases can be set up to solve for the unknown forces, utilizing the relationship between force, mass, and acceleration. This approach will yield the magnitudes of FA and FB based on the given conditions.
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Hey guys, need a little help. Can someone point me in the right direction for this question? I just need to know where to start.

Two forces FA and FB are applied to an object whose mass is 8.27 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.57 m/s2. However, when FA points due east and FB points due west, the acceleration is 0.35 m/s2, due east.

(a) Find the magnitude of FA
(b) Find the magnitude of FB
 
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Hi JJones_86,

JJones_86 said:
Hey guys, need a little help. Can someone point me in the right direction for this question? I just need to know where to start.

Two forces FA and FB are applied to an object whose mass is 8.27 kg. The larger force is FA. When both forces point due east, the object's acceleration has a magnitude of 0.57 m/s2. However, when FA points due east and FB points due west, the acceleration is 0.35 m/s2, due east.

(a) Find the magnitude of FA
(b) Find the magnitude of FB

How are the forces related to acceleration?
 
case one

i-Fnet,x= FA cos(0)+FBcos(0)=ma

0- because they are in the orginal x-axis and pointed to the right

a=0.57 m/s2


case two

do the same thing what i did in case one

Fnet,x= FA cos(0)+FA cos(180)=ma,,, (a here is .35)
180 because it is ponited to the left

u have two equation with two unkowns
 
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