Chemistry Find mass from mole frac and solution mass

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To find the masses of propane and butane in a 75g gaseous mixture with a mole fraction of 0.51 for propane, the total moles of the gases must be calculated using their mole fractions. The equation X = mol A / mol total helps establish the relationship between the moles of propane and butane. The initial attempt to set up equations using the mole fractions was incorrect, as it did not incorporate the total mass of the mixture effectively. A correct approach involves using the mass of each component and their respective molar masses to solve for the individual masses of propane and butane. This requires setting up a system of equations that includes both the total mass and the mole fraction relationships.
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1. 75g sample of a gaseous mixture contains .51 mole fraction propane. The remainder is butane. What are the masses of propane and butane?



2. X = mol A / mol total



The Attempt at a Solution


P = mol propane
B = mol butane
I tried doing .49P + .49B = X mol propane and .51P + .51B = Y mol butane however that doesn't seem to be solvable. I'm not quite sure how I should manipulate the 75 g of solution.
 
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0.49B + 0.51P = n

second equation must contain masses of both gases - what is a mass of 0.49B?
 
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