Find Min Distance b/w Parabolas: 7/(4*root2)

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The minimum distance between the curves defined by the equations y^2 - xy - 2x^2 = 0 and y^2 = x - 2 is calculated to be 7/(4*root2). The first equation can be factored into two linear components, y = -x and y = 2x, simplifying the analysis. A graph of these lines indicates that y = -x is closer to the second curve. By applying the slope form of the tangent to the parabola, the distance between the two parallel lines was determined. This approach effectively resolves the problem using fundamental concepts of parabolas and distance calculations.
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Homework Statement


Find the minimum distance between the curves y^2 - xy - 2x^2 = 0 and y^2 = x - 2.
Ans: 7/(4*root2)

Homework Equations

The Attempt at a Solution


It's supposed to be done using concepts from parabolas. I tried using calc but it got convoluted.
 
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erisedk said:

Homework Statement


Find the minimum distance between the curves y^2 - xy - 2x^2 = 0 and y^2 = x - 2.
Ans: 7/(4*root2)

Homework Equations

The Attempt at a Solution


It's supposed to be done using concepts from parabolas. I tried using calc but it got convoluted.

y^2 - xy - 2x^2 splits into two linear factors. That makes it easier since the graph becomes two lines.
 
Ohhh ok. I didn't realize that was a pair of straight lines.
I did it now. Split it into y=-x and y=2x. Drew a rough graph. It's clear from the graph that y=-x is closer. So, using the slope form of tangent to a parabola, I wrote the equation of tangent with the slope -1, and figured out the distance between the two parallel lines, which comes out to be the answer. Thanks :D
 
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