Find molar absorptivity given the following

[ssb]

Homework Statement

Calculate the molar absorptivity of K2Cr2O7 at 455 nm given that 36.5 mg disolved in 500.0 mL exhibits 12.0% transmittance at 455 nm in a 2.000 cm cell.

Homework Equations

Beers law E = A/bc

The Attempt at a Solution

I was able to do the following part ( i solved for concentration of K2Cr2O7 )
I found the atomic mass of K2Cr2O7
[(0.0365 g)/(294.07 g/mol)] / (0.5000 L) = 2.482 x 10^-4

Now I plug this into beers law but the question asks for something about a 12.0% transmittance. I am stuck here. How does transmittance relate to molar absorptivity?

I basically have 2 unknowns in one equation... what do I need to do next?

E = A / [(2.000 cm)(2.482 x 10^-4)] and I need to solve for A.

 

[ssb]

Does A = -log(.12)= .0921 ?

and if this is the case

E = 0.0921 / [(2.000 cm)(2.482 x 10^-4)] = 185.5359 ? are sig figs correct as well?

 

[chemisttree]

Which number in your calculation has the fewest sig figs? How many are there? How many are in your answer?