Find Net Force of 2.5x10^5N Training Helicopter

In summary, the conversation was about finding the net force of a training helicopter at t=5.0s, given its position and acceleration. The net force can be calculated using Newton's 2nd law, which states that net force is equal to mass times acceleration. The force can be expressed in the form of its x, y, and z components.
  • #1
xmflea
44
0
The position of a 2.5x10^5N training helicopter under test is given by
r=(0.020m/s^3)t^3i + (2.2m/s)tj-(0.060m/s^2)t^2k , find the net force of the helicopter at t=5.0s

express F in the form Fx Fy and Fz

F=ma F=Fx+Fy+Fz


so far i plugged in t to each component to get 2.5m, 11m, and 1.5 m,
now i just need to know how to use the force that is given to find the x, y, and z components. need a little guidance.
 
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  • #2
The net force is not given, you have to figure it out. What does Newton's 2nd law say about net force? (That should give you a hint about what you need to do.)
 
  • #3


I would approach this problem by first understanding the basic principles of force and motion. The net force is the overall force acting on an object, which is equal to the mass of the object multiplied by its acceleration. In this case, the net force of the helicopter can be calculated using the equation F=ma, where F is the net force, m is the mass of the helicopter, and a is the acceleration.

To find the net force at t=5.0s, we need to plug in the values for the mass and acceleration of the helicopter. The mass of the helicopter is not given in the problem, so we cannot calculate the net force directly. However, we can use the given position vector to find the acceleration of the helicopter at t=5.0s.

To do this, we can use the equation a=d^2r/dt^2, where a is the acceleration, r is the position vector, and t is time. By differentiating the position vector with respect to time twice, we can find the acceleration at t=5.0s.

Once we have the acceleration, we can plug it into the equation F=ma to find the net force of the helicopter at t=5.0s. This net force will have three components: Fx, Fy, and Fz, corresponding to the x, y, and z directions respectively.

To find these components, we can use the fact that the position vector r is given in terms of i, j, and k unit vectors. This means that the x component of the net force, Fx, will be equal to the mass of the helicopter multiplied by the x component of the acceleration. Similarly, the y and z components of the net force, Fy and Fz, will be equal to the mass of the helicopter multiplied by the y and z components of the acceleration, respectively.

In summary, to find the net force of the helicopter at t=5.0s, we need to first calculate the acceleration of the helicopter at that time using the given position vector. Then, we can use the equation F=ma to find the net force, which will have three components: Fx, Fy, and Fz. These components can be found by multiplying the mass of the helicopter by the x, y, and z components of the acceleration, respectively.
 

1. What is the formula for finding net force?

The formula for finding net force is Fnet = ΣF = ma, where Fnet is the net force, ΣF is the sum of all forces acting on the object, and m is the mass of the object.

2. How do you calculate the net force of a 2.5x10^5N training helicopter?

To calculate the net force of a 2.5x10^5N training helicopter, you need to determine all the forces acting on the helicopter, such as the weight, lift, thrust, and drag. Then, use the formula Fnet = ΣF = ma to calculate the net force.

3. What is the significance of finding the net force of a training helicopter?

Finding the net force of a training helicopter is important because it helps us understand the overall forces acting on the helicopter and how they affect its motion. This information can be used to make adjustments and improvements to the helicopter's design and performance.

4. Can the net force of a training helicopter be negative?

Yes, the net force of a training helicopter can be negative. A negative net force indicates that the forces acting on the helicopter are in the opposite direction, causing it to slow down or move in the opposite direction.

5. How does the net force affect the acceleration of a training helicopter?

The net force directly affects the acceleration of a training helicopter. According to Newton's Second Law of Motion, the acceleration of an object is directly proportional to the net force acting on it. This means that a larger net force will result in a greater acceleration, and a smaller net force will result in a smaller acceleration.

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