Find Net Force of 2.5x10^5N Training Helicopter

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SUMMARY

The net force acting on a 2.5x10^5N training helicopter can be calculated using Newton's second law, F=ma, where the position vector is defined as r=(0.020m/s^3)t^3i + (2.2m/s)tj-(0.060m/s^2)t^2k. At t=5.0s, the position components yield values of 2.5m, 11m, and 1.5m for the x, y, and z directions, respectively. To find the net force components Fx, Fy, and Fz, one must differentiate the position vector to obtain velocity and then differentiate again to find acceleration, which can then be multiplied by the mass of the helicopter to determine the net force.

PREREQUISITES
  • Understanding of Newton's second law (F=ma)
  • Knowledge of vector calculus for differentiation
  • Familiarity with kinematic equations
  • Basic concepts of force and motion in physics
NEXT STEPS
  • Calculate the acceleration components by differentiating the position vector r with respect to time.
  • Determine the mass of the helicopter to apply Newton's second law effectively.
  • Explore vector representation of forces in three-dimensional space.
  • Review examples of net force calculations in physics problems.
USEFUL FOR

Physics students, aerospace engineers, and anyone involved in dynamics and motion analysis of vehicles, particularly in aerospace applications.

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The position of a 2.5x10^5N training helicopter under test is given by
r=(0.020m/s^3)t^3i + (2.2m/s)tj-(0.060m/s^2)t^2k , find the net force of the helicopter at t=5.0s

express F in the form Fx Fy and Fz

F=ma F=Fx+Fy+Fz


so far i plugged in t to each component to get 2.5m, 11m, and 1.5 m,
now i just need to know how to use the force that is given to find the x, y, and z components. need a little guidance.
 
Physics news on Phys.org
The net force is not given, you have to figure it out. What does Newton's 2nd law say about net force? (That should give you a hint about what you need to do.)
 

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