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Homework Statement
A practical current source has a current of 22 A. Loading the source with 50 \Omega results in terminal voltage of 390.3 V. Obtain the source constants, I and R.
Homework Equations
V=I\times R
The Attempt at a Solution
In my clumsy picture below, shouldn't I_{load} be replaced by the I of the "practical current source"? That is, isn't a "practical current source" as a black box, and we can only "see" the outside current?
[PLAIN]http://img51.imageshack.us/img51/1466/dsc01001ni.jpg
Only if I take the current outside as I_{load} (and not as the I itself) do I get the correct solution:
I_{load}=\frac{V}{R_{load}}=\frac{390.3V}{50 \Omega}=7.806 A
R=\frac{V}{I_R}=\frac{V}{I-I_{load}}=\frac{390.3 V}{22A - 7.806 A}\dot{=}27.5 \Omega
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