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Find residue of exp(1/(z+i))

  1. Jun 14, 2012 #1
    Hi, I want to know how you find the residue of z=-i for the function exp(1/(z+i)). Clearly, the function has an essential singularity at z=-i so the good ol' formula for the residue for a pole of order m, doesn't really work here. What do I do? :)
  2. jcsd
  3. Jun 14, 2012 #2
    You expand the function as a Laurent series around the pole and recall that the residue at that point is the coefficient in front of term proportional to [itex]\frac{1}{z+i} [/itex]
  4. Jun 14, 2012 #3
    okay, can you help me how that is done. My book's section os Laurent series is quite poor. The only thing I know about expanding functions as them, is that you can sometimes use geometric series. You don't need to say how I should do it, just hint me at where to start.
  5. Jun 14, 2012 #4
    Just expand e^x as a usual Taylor series, then plug in x=1/(z+i) and it's done!
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