Find Resonant Frequency of Spring-Mass-Dashpot System

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The discussion focuses on finding the resonant frequency of a spring-mass-dashpot system driven by a sinusoidal force. The correct expression for the resonant frequency when H is positive is identified as sqrt(k/m - b^2/(2*m^2)). However, complications arise when considering cases where H is negative or zero, as high damping (large b) prevents the system from oscillating naturally. Participants explore the implications of negative H and attempt to derive the correct equations for these scenarios. Ultimately, the challenge lies in accurately expressing the resonant frequency under conditions of high damping.
Poetria
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Homework Statement


Consider the spring-mass-dashpot system driven by a sinusoidal force on the mass:

(mD2+bD+k)x=F where sin(omega*t)

Recall that for the unforced underdamped oscillator (b^2<4km, F=0), the value of the natural damped frequency omega_d=sqrt(k/m - b^2/(4m^2)
Find the resonant (angular) frequency omega_r.

That is, find the angular frequency at which the gain of the response attains its maximum.

(This resonant frequency will be in the form sqrt(H) for some expression H. Assume H>0)
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f(omega)=(k-m*omega^2)^2+b^2*omega^2
f'(omega=-4*m*omega*(k-m*omega^2)+2*b^2*omega=0

I got this one right - sqrt(k/m-b^2/(2*m^2)) :)
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Now I have a problem:
Finally, what happens if the expression H is negative or zero? Find the angular frequency omega at which the gain attains its maximum for the case when H is less or equal to 0.

Switching signs does not help. :(

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Poetria said:

Homework Statement


Consider the spring-mass-dashpot system driven by a sinusoidal force on the mass:

(mD2+bD+k)x=F where sin(omega*t)

Recall that for the unforced underdamped oscillator (b^2<4km, F=0), the value of the natural damped frequency omega_d=sqrt(k/m - b^2/(4m^2)
Find the resonant (angular) frequency omega_r.

That is, find the angular frequency at which the gain of the response attains its maximum.

(This resonant frequency will be in the form sqrt(H) for some expression H. Assume H>0)
----
f(omega)=(k-m*omega^2)^2+b^2*omega^2
f'(omega=-4*m*omega*(k-m*omega^2)+2*b^2*omega=0

I got this one right - sqrt(k/m-b^2/(2*m^2)) :)
---
Now I have a problem:
Finally, what happens if the expression H is negative or zero? Find the angular frequency omega at which the gain attains its maximum for the case when H is less or equal to 0.

Switching signs does not help. :(

----
Your H is negative if b is big enough but that would mean that the damping is so big that the system won't have any resonant frecuency because there is no chance that it naturally oscilates( it means With F=0)
 
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Diegor said:
Your H is negative if b is big enough but that would mean that the damping is so big that the system won't have any resonant frecuency because there is no chance that it naturally oscilates( it means With F=0)

Yes, I do know it but how to write the equation? I thought it would be sqrt(k/m-b^2/(4*m^2)) but it is wrong. :( If I assume that
-(k-m*omega^2)^2+b^2*omega^2) I get the same result through differentiation.
 
Ok. Many thanks. I got it. :)
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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