Find Serret-Frenet Triad for Curve y = f(x): Solve Diff. Eq. -U`(s)

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The discussion focuses on finding the Serret-Frenet Triad for the curve y = f(x) and solving the differential equation U`(s) with U = x^2/2. It describes the resultant vector force acting on a bead and the method to derive it through multiplication of vectors. A crucial point raised is that the solution leads to a cycloid, indicating a potential error in the approach. Additionally, there is clarification sought regarding the notation of derivatives represented by grave accents in the equations. The conversation emphasizes the importance of correctly interpreting the differential equation in the context of particle motion in a potential.
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Homework Statement
Consider the motion of a particle in a potential: x`` = −U`(x). Can this equation also describe the arclength parameter of a bead sliding under gravity on an appropriately shaped wire? That is, find the curve y = V (x) such that the arc length parameter s of a bead sliding on this curve under
gravity (g = const. pointing down the y-axis) satisfies the same equation: s`` = −U`(s), and state under what conditions on U this is possible. Find V in the following two cases: (i) U = x^2/2 and (ii) U = −cos x.
Relevant Equations
Serret-Frenet Triad, F=ma
For the case first case U=x^2/2 :
1) Find the Serret-Frenet Triad for a any curve y = f(x):
For a curve on a plane, the Triad could be find in this way:
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2) The vector force resultant acting in the bead could be discribed in this way:
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3) The vector force acting in the bead could be discribed in this way:
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4) Multypling (3) with (1) and equalizing to (2):

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5) From the question, we know that (4) is equal to -U`(s), so solving the differential equation, we have:
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6) But the answer is a cycloid , so there is somethig wrong.
 
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hilton said:
Problem Statement: Consider the motion of a particle in a potential: x`` = −U`(x). Can this equation also
What do the grave accents (` ) mean in this x`` , `( notation?
 
The derivative
 
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