The discussion focuses on finding the smallest value of k in the equations n^(5/3) = m^(7/2) and nm = p^k, where m, n, p, and k are positive whole numbers greater than 1. The analysis reveals that k must be a multiple of 31 for m and n to remain whole numbers, leading to the conclusion that the smallest valid k is 31. The reasoning includes ensuring that expressions like p^(10k/31) yield integers, which further supports k = 31 as the only feasible solution. Ultimately, the answer is determined to be option C, 31. This conclusion is reached through a combination of algebraic manipulation and consideration of integer constraints.